0=12-0.03s^2

Solution for 0=12-0.03s^2 equation:

0=12-0.03s^2

We move all terms to the left:

0-(12-0.03s^2)=0

We add all the numbers together, and all the variables

-(12-0.03s^2)=0

We get rid of parentheses

0.03s^2-12=0

a = 0.03; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·0.03·(-12)
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.44}}{2*0.03}=\frac{0-\sqrt{1.44}}{0.06}
=-\frac{\sqrt{}}{0.06}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.44}}{2*0.03}=\frac{0+\sqrt{1.44}}{0.06}
=\frac{\sqrt{}}{0.06}
$